1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
|
# mod_37_2.py - functions for performing the ISO 7064 Mod 37, 2 algorithm
#
# Copyright (C) 2010-2021 Arthur de Jong
#
# This library is free software; you can redistribute it and/or
# modify it under the terms of the GNU Lesser General Public
# License as published by the Free Software Foundation; either
# version 2.1 of the License, or (at your option) any later version.
#
# This library is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
# Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public
# License along with this library; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA
# 02110-1301 USA
"""The ISO 7064 Mod 37, 2 algorithm.
The Mod 37, 2 checksum can be used for alphanumeric numbers and the check
digit may also be numeric, a letter or '*'.
>>> calc_check_digit('G123489654321')
'Y'
>>> validate('G123489654321Y')
'G123489654321Y'
>>> checksum('G123489654321Y')
1
By changing the alphabet this can be turned into any Mod x, 2
algorithm. For example Mod 11, 2:
>>> calc_check_digit('079', alphabet='0123456789X')
'X'
>>> validate('079X', alphabet='0123456789X')
'079X'
>>> checksum('079X', alphabet='0123456789X')
1
"""
from stdnum.exceptions import *
def checksum(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ*'):
"""Calculate the checksum. A valid number should have a checksum of 1."""
modulus = len(alphabet)
check = 0
for n in number:
check = (2 * check + alphabet.index(n)) % modulus
return check
def calc_check_digit(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ*'):
"""Calculate the extra digit that should be appended to the number to
make it a valid number."""
modulus = len(alphabet)
return alphabet[(1 - 2 * checksum(number, alphabet)) % modulus]
def validate(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ*'):
"""Check whether the check digit is valid."""
try:
valid = checksum(number, alphabet) == 1
except Exception: # noqa: B902
raise InvalidFormat()
if not valid:
raise InvalidChecksum()
return number
def is_valid(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ*'):
"""Check whether the check digit is valid."""
try:
return bool(validate(number, alphabet))
except ValidationError:
return False
|