# mod_37_2.py - functions for performing the ISO 7064 Mod 37, 2 algorithm # # Copyright (C) 2010, 2011, 2012 Arthur de Jong # # This library is free software; you can redistribute it and/or # modify it under the terms of the GNU Lesser General Public # License as published by the Free Software Foundation; either # version 2.1 of the License, or (at your option) any later version. # # This library is distributed in the hope that it will be useful, # but WITHOUT ANY WARRANTY; without even the implied warranty of # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU # Lesser General Public License for more details. # # You should have received a copy of the GNU Lesser General Public # License along with this library; if not, write to the Free Software # Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA # 02110-1301 USA """The ISO 7064 Mod 37, 2 algorithm. The Mod 37, 2 checksum can be used for alphanumeric numbers and the check digit may also be numeric, a letter or '*'. >>> calc_check_digit('G123489654321') 'Y' >>> is_valid('G123489654321Y') True >>> checksum('G123489654321Y') 1 By changing the alphabet this can be turned into any Mod x, 2 algorithm. For example Mod 11, 2: >>> calc_check_digit('079', alphabet='0123456789X') 'X' >>> is_valid('079', alphabet='0123456789X') True >>> checksum('079', alphabet='0123456789X') 1 """ def checksum(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ*'): """Calculate the checksum. A valid number should have a checksum of 1.""" modulus = len(alphabet) check = 0 for n in number: check = (2 * check + alphabet.index(n)) % modulus return check def calc_check_digit(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ*'): """With the provided number, calculate the extra digit that should be appended to make it a valid number.""" modulus = len(alphabet) return alphabet[(1 - 2 * checksum(number, alphabet)) % modulus] def is_valid(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ*'): """Checks whether the check digit is valid.""" try: return bool(number) and checksum(number, alphabet) == 1 except: return False