# cpf.py - functions for handling CPF numbers # coding: utf-8 # # Copyright (C) 2011, 2012 Arthur de Jong # # This library is free software; you can redistribute it and/or # modify it under the terms of the GNU Lesser General Public # License as published by the Free Software Foundation; either # version 2.1 of the License, or (at your option) any later version. # # This library is distributed in the hope that it will be useful, # but WITHOUT ANY WARRANTY; without even the implied warranty of # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU # Lesser General Public License for more details. # # You should have received a copy of the GNU Lesser General Public # License along with this library; if not, write to the Free Software # Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA # 02110-1301 USA """CPF (Cadastro de Pessoas FĂ­sicas, Brazillian national identifier). >>> is_valid('390.533.447-05') True >>> is_valid('231.002.999-00') False >>> compact('390.533.447-05') '39053344705' >>> format('23100299900') '231.002.999-00' """ from stdnum.util import clean def compact(number): """Convert the number to the minimal representation. This strips the number of any valid separators and removes surrounding whitespace.""" return clean(number, ' -.').strip() def _calc_check_digits(number): """Calculate the check digits for the number.""" d1 = sum((10 - i) * int(number[i]) for i in range(9)) d1 = (11 - d1) % 11 % 10 d2 = sum((11 - i) * int(number[i]) for i in range(9)) + 2 * d1 d2 = (11 - d2) % 11 % 10 return '%d%d' % (d1, d2) def is_valid(number): """Checks to see if the number provided is a valid BSN. This checks the length and whether the check digit is correct.""" try: number = compact(number) except: return False return len(number) == 11 and \ number.isdigit() and \ int(number) > 0 and \ _calc_check_digits(number) == number[-2:] def format(number): """Reformat the passed number to the standard format.""" number = compact(number) return number[:3] + '.' + number[3:6] + '.' + number[6:-2] + '-' + number[-2:]